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Mar 20, 2019 at 16:35 answer added Prestosaurus timeline score: 1
Mar 19, 2019 at 16:06 comment added Prestosaurus Maybe I need to ask another question. If I implement $form_state->setRebuild(TRUE) via a submit form element, I am not sure how to get the altered/active field value, not the [#default_value].
Mar 19, 2019 at 14:30 comment added 4uk4 See Examples, when you set $nojs in the ajax examples you get dynamic forms rebuilding without #ajax: cgit.drupalcode.org/examples/tree/ajax_example/src/Form
Mar 19, 2019 at 13:30 comment added 4uk4 To avoid the error use isset(). For dynamic forms in general, try to not submit and save the values until the end. Rebuild the form instead, then check in buildForm() the value of field_number in $form_state and build the dynamic form elements accordingly.
Mar 19, 2019 at 3:34 history edited Prestosaurus CC BY-SA 4.0
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Mar 19, 2019 at 3:31 comment added Prestosaurus The error comes from '#default_value' => $config->get('field')[$i]. So if you have 1 field and add 100, you get 100 notices of undefined offset. Not sure how to get an un-submitted form field value into $form_state as form fields don't have any type of '#onblur'or anything as far as I know. Hoping to add 100+/- fields in one click.
Mar 19, 2019 at 2:52 comment added Jaypan Which line is throwing the error? Also note that if you add form elements without Drupal #ajax, you will get an error. When using the form API, you MUST use #ajax to add/remove form fields. There is no other option.
Mar 19, 2019 at 0:55 history edited Prestosaurus CC BY-SA 4.0
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Mar 18, 2019 at 18:03 history asked Prestosaurus CC BY-SA 4.0