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I have the nodes that have the source image field field_old_image_field and the destination image field, field_new_image_field. field_old_image_fieldhas only one image. field_new_image_fieldcan have multiple images and probably does. I need to copy the image from field_old_image_field to field_new_image_field without disturbing the images that are already in field_new_image_field.

Here's my code so far:

foreach ($nodes as $node) {  
    if ($node->hasField('field_old_image_field') && !empty($node->field_old_image_field->target_id)) {
      $image = $node->get('field_old_image_field');
      $image_uri = $image->entity->getFileUri();
      $image_alt = $image[0]->get('alt')->getString();
      $image_title = $image[0]->get('title')->getString();

      $node->get('field_new_image_field')->appendItem([
        'target_id' => $image,
        'alt' => $image_alt,
        'title' => $image_title,
      ]);
    }

    $node->save();
  }

But when I run this code in an update hook, I get

In EntityReference.php line 106:

Value is not a valid entity.

I was getting it to work earlier, but I wasn't getting the alt text or the title text copied over. What's wrong with this code and is there an easier way to do this?

1 Answer 1

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The first line doesn't get you an image, it's a field item list:

$items = $node->get('field_old_image_field');

Then you can get the first item

$item = $items[0];

and append the item properties to the new field:

$node->get('field_new_image_field')->appendItem([
  'target_id' => $item->target_id,
  'alt' => $item->alt,
  'title' => $item->title,
]);
1
  • Very nice. Thank you.
    – esod
    Commented Jul 18, 2020 at 16:05

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