i have a content type and it stores user_email,title,body etc.

Every node has a URL alias.

How can i go through all the node, and extract the email field + the URL of that node.

any clue . thanks

  • you mean you want fetch all email_field and url alias of all nodes?
    – Yuseferi
    Apr 6, 2014 at 8:27
  • Do you want get specify content type?
    – Yuseferi
    Apr 6, 2014 at 8:28
  • yes , i want to fetch all email_field and url alias of all nodes.
    – brainHax
    Apr 6, 2014 at 9:17
  • good, do you want get specified content type?
    – Yuseferi
    Apr 6, 2014 at 9:19

2 Answers 2


If you want get node of page content type ,you can try another content types

$type = "page"; // machine name for Basic Page
$nodes = node_load_multiple(array(), array('type' => $type)); 
foreach($nodes as $node){
     arr[$node->nid]['email']= $node->field_email['und'][0]['value'];
     arr[$node->nid]['url_alias']= drupal_get_path_alias('node/'. $node->nid);
  • great. Is there a way that i can put the above code in a file like export.php and run it directly like mywebsite.com/export.php. ? i dont want to ad it in a template file
    – brainHax
    Apr 6, 2014 at 9:31
  • no,you cant put it in .php file , (of course there is way to do it but not recommended),put it in your custom module
    – Yuseferi
    Apr 6, 2014 at 10:47
  • @brainHax you can create a menu link (mywebsite.com/export) from module using hook_menu and output the array in table format ..using theme() function.. Incase if you dont want it in template.
    – shrish
    Apr 7, 2014 at 3:04

You can get url of any particular node using this function

$alias = drupal_get_path_alias('node/102');

Getting email of any node use following statement

$node = node_load(102);
$email = $node->field_email['und'][0]['email']

Make sure I am getting these details of NodeID 102 in above example.

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