I am trying to create a custom view page template which will be made of custom fields, which i am trying to print. I created a view page and added all the needed fields to it.

Next, I created a views-view--my-page-name.tpl.php template, which get's recognised, however when i try to print the fields, i get the errors below:

Notice: Undefined variable: fields in include...

Notice: Trying to get property of non-object in include....

Below is the full code of my custom view page template which i copied from the default view page template and modified it. Im trying to print the field with this code:

<?php print $fields['views_field_field_name']->content; ?>

I tried all variables of field name as: field_name, field_field_name, views_field_field_name, but none of them work, as they all give same error.

<div class="<?php print $classes; ?>">
  <?php print render($title_prefix); ?>
  <?php if ($title): ?>
    <?php print $title; ?>
  <?php endif; ?>
  <?php print render($title_suffix); ?>

  <?php if ($exposed): ?>
    <div class="view-filters">
      <?php print $exposed; ?>
  <?php endif; ?>

  <?php print $pager; ?>

  <?php if ($header): ?>
    <div class="view-header">
      <?php print $header; ?>
  <?php endif; ?>

  <?php if ($attachment_before): ?>
    <div class="attachment attachment-before">
      <?php print $attachment_before; ?>
  <?php endif; ?>

<?php print $fields['views_field_field_name']->content; ?>
<?php print $fields['views_field_field_age']->content; ?>
<?php print $fields['views_field_field_phone']->content; ?>

  <?php print $pager; ?>

  <?php if ($footer): ?>
    <div class="view-footer">
      <?php print $footer; ?>
  <?php endif; ?>

  <?php if ($attachment_after): ?>
    <div class="attachment attachment-after">
      <?php print $attachment_after; ?>
  <?php endif; ?>

  <?php if ($more): ?>
    <?php print $more; ?>
  <?php endif; ?>  

  <?php if ($feed_icon): ?>
    <div class="feed-icon">
      <?php print $feed_icon; ?>
  <?php endif; ?>

</div><?php /* class view */ ?>

1 Answer 1


You are using template for display, here you will do theming for overall display, the $fields variable is not available here.

If you want to change how fields are printed relative to each other, row style, then you should use views-view-fields.tpl.php, in your case the name will be like views-view-fields--yourpagename.tpl.php.

but if you want to theme individual fields then you have to use views-view-field--yourfieldname.tpl.php.

  • Im using the display template beacuse i only want to put a wrapper around the printed fields. I don't want to make any changes to the fields except to put each of them in a wrapper with a different class each, separately, so i can theme them. How could i just print the Label + Content of the fields on the display template?
    – risha riss
    Commented Jun 29, 2014 at 8:29
  • Create a template file like views-view-fields--yourpagename.tpl.php and copy the contents from views-view-fields.tpl.php and add your wrapper.
    – msmani
    Commented Jun 29, 2014 at 8:36
  • But wouldn't that add the wrapper with same class to all fields? I want to add wrapper with different class around each field.
    – risha riss
    Commented Jun 29, 2014 at 8:37
  • You will be having field name & label based on that you can create your wrapper.
    – msmani
    Commented Jun 29, 2014 at 8:54
  • I did as you suggested. Below is the code i have in my view-fields--mypagename.tpl.php <div class="col-sm-12"> <?php foreach ($fields as $id => $field): ?> <?php if (!empty($field->separator)): ?> <?php print $field->separator; ?> <?php endif; ?> <div class="col-sm-3"> <?php print $field->wrapper_prefix; ?> <?php print $field->label_html; ?> <?php print $field->content; ?> <?php print $field->wrapper_suffix; ?> </div> <?php endforeach; ?> </div> But this put class="col-sm-3" wrapp around each field. How could i use different class on each field wrapp.
    – risha riss
    Commented Jun 29, 2014 at 8:59

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