Notice Error UND

Question

I have a error that keeps popping up through my website after I added tags to print custom user profile fields. The code i'm using is

<?php 
global $user;
$user_fields = user_load($user->uid);
$name = $user_fields->field_name;
$department = $user_fields->field_department;
?>
<?php

to pint the fields i'm using

<?php print $name['und'][0]['value'];?>
<?php print $department['und'][0]['value'];?>

i'm not sure if this is the correct way to do this or if there is a better way. I tried to remove [0] and the tag no longer works. I have also tried to use the following:

  <?php if (!empty($action_links)): ?>
  <?php print $name['und'][0]['value'];?>
  <?php endif ?>

This again did not display the custom field.

Answer 1

The proper way to print fields in Drupal 7 is to use field_view_field() to fetch a renderable array that can be passed to dupal_render() like so:

<?php
  global $user;
  $user = user_load($user->uid);
  print drupal_render(field_view_field('user', $user, 'field_name'));
  print drupal_render(field_view_field('user', $user, 'field_department'));
?> 

This is also true for $node objects FYI.

Answer 2

If you are wanting to render the field as drupal would in the "manage display" then use Webdrips answer. If you are simple wanting to render the value and have the entity API then you can do this:

<?php 
  global $user;
  $user = user_load($user->uid);
  $user_wrapper = entity_metadata_wrapper('user', $user);
  $name = $user_wrapper->field_name->value();
  $department = $user_wrapper->field_department->value();
?>
<?php
  print $name;
  print $department;
?>

Answer 3

These are the warnings because you are accessing any indexes that are not present in that field. Mainly occurres when these fields are not entered so these indexes are not created. You can use it with the isset to avoid these error/warnings

<?php print isset($name['und'][0]['value']) ? $name['und'][0]['value'] : "";?>
<?php print isset($department['und'][0]['value']) ? $department['und'][0]['value'] "";?>

OR

You can use the default drupal method to print field using field_view_field() function as mention in the earlier answer.

<?php
global $user;
$userFull = user_load($user->uid);
print render(field_view_field('user',$userFull,'field_name',$display=array() ));
//Where $display handles the label(hidden or to show), format etc
?>

Hope it will help!