I have a views that include node title, a text field and a taxonomy term reference field.

I need to print the taxonomy term name via Global: PHP field (Views PHP) but I couldn't.

How to print taxonomy term name with Views PHP?

I can print the node title with that code:

Value Code:

return $row->title; 

Output Code:

<?php print $value; ?>

or without Value Code:

Output Code:

<?php print $row->title; ?>

And I could print the taxonomy term ID with that code:

Output Code:

<?php print $data->field_field_my_taxonomy_term[0]['raw']['tid']; ?>

But using name or value instead of tid doesn't return anything.

I also tried to print the term name with these ones but unfortunately none of them worked:


(Above code prints nothing.)

<?php $data->field_my_taxonomy_term[0]['raw']['taxonomy_term']->name; ?>

(Above code prints nothing.)

So, I'm confused now and not know how to print taxonomy term name with Views PHP?

Note: I looked at these but still couldn't solve the problem:

  1. Views Php how to select actual term name not term ID

  2. https://www.drupal.org/node/1707002

  3. https://www.drupal.org/node/1516348

2 Answers 2


Unless the term name is in the query for the View, you'll need to load the object to get its properties:

$term = taxonomy_term_load($data->field_field_my_taxonomy_term[0]['raw']['tid']);
$name = $term->name;

That will incur a performance cost, so it would be better to add the relationship to the term in the View itself, and add the name as a hidden field. Then you can refer to it without having to load any entities.

  • Actually, the term name was in the query for the View but didn't work. Now, it's working correctly and I'm very surprised to see the result. Thanks a lot. And a note for the friends in the same situation: my actual field name is field_my_taxonomy_term and in the code above doesn't work without adding the field_ before field_my_taxonomy_term (so it becomes field_field_my_taxonomy_term). My mistake was that.
    – herci
    Jun 30, 2015 at 10:15
  • How can I use the code above for multiple terms instead of one? I tried to add a foreach loop but didn't work. If all the nodes have equal numbers of terms it's may be easy but each node can have 0 to 7 terms.
    – herci
    Jun 30, 2015 at 11:42
  • 1
    Yep foreach or for, either is fine. Can't tell you which/how as I can't see your data, but it should be straightforward in theory
    – Clive
    Jun 30, 2015 at 12:07
  • For multiple terms you can use that code: foreach($data->field_field_my_taxonomy as $mydata) { $term = taxonomy_term_load($mydata['raw']['tid']); ... }
    – herci
    Jun 30, 2015 at 21:12

Storing PHP code directly on database is not a correct method, it causes many issues. Better you can add the relations on your views - "Content: Taxonomy terms on node". and then add the taxonomy term name field as a "hidden field"

Print the value via "Global: Custom text" field if required any custom wrapper around of it.

  • Yes, I know "storing PHP code directly on database" is not a good way but I'm using this View just for a while (to export data). And because I'm manipulating the term name, using "Global: Custom text" doesn't work for this case. Thanks.
    – herci
    Jun 30, 2015 at 10:43

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