1

I would like to display the rank position of a node based on a field value.

Let's say that in field_A there is the node's quantity of "points" and in field_B the node's category.

Then, I would like to display that the current node is 5th out of 15 in its category for example.

thanks for your help.

9
  • How do you want to handle ties?
    – Ollie
    Jul 24, 2015 at 13:09
  • I don't know yet. Any idea?
    – yohan sube
    Jul 24, 2015 at 13:15
  • en.wikipedia.org/wiki/Ranking
    – Ollie
    Jul 24, 2015 at 17:36
  • can you write code, or do you need to do this as a view?
    – Ollie
    Jul 24, 2015 at 17:36
  • Whatever, view or code in a field (computed field) will be fine
    – yohan sube
    Jul 24, 2015 at 17:38

1 Answer 1

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seems you need to create a "taxonomy view" (category) then create a listing and sort them by the "points" field value.

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  • Thanks a lot. But I need to show only the current node position. With this method it displays all nodes
    – yohan sube
    Jul 24, 2015 at 14:00
  • If you want to create a (table)list like: 1.node x 2.node y 3,node z U can use the display field :global counter. Jus showing one node can be done by filter or using a contextual filter.
    – pindaman
    Jul 25, 2015 at 10:17
  • The problem is that when U use a filter and so display 1 result, the global counter will be always 1. It doesn't keep the rank that was before filtering.
    – yohan sube
    Jul 25, 2015 at 10:37

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