What I really want is that I have a block and I want it to be shown only for authenticated users.
Can anyone help me?
Note: I want to do it programmatically without an extra module.
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admin is also authenticated, is that what you want?– Paul BönischOct 1, 2015 at 12:31
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1Possible duplicate of drupal.stackexchange.com/questions/69861/… (assigning access to the "authenticated user" role in your case). BTW, it would be useful to edit the original question to mention that you want to do it programmatically ;)– dinopmiOct 1, 2015 at 12:52
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4 Answers
global $user;
check $user->roles and unset your block:
function modulename_block_list_alter(&$blocks){
global $user;
$roles = $user->roles;
if(!in_array('authenticated user', $roles)){
unset($blocks[6]);
}
// 6 is actually a block id witch is
//an array key from $blocks
}
I have just tested it with simpletest and it works. You need to check the user roles also.
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global $user; if (!isset($user->uid)) { unset($blocks[19]); } this does not work for me– KarmenOct 1, 2015 at 13:19
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global $user; if ($user->uid = 0) { unset($blocks[19]); } It also does not work again...– KarmenOct 1, 2015 at 13:37
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with $user->uid = 0 you just assignet 0 to $user->uid. Replace it with $user->uid == 0 or even better take a look on my last edit;) Oct 1, 2015 at 13:38
Check out this module block access
there is the option of assigning a role in the block settings under the Visibility settings.
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use php code for the body section and put the condition
if($user == admin) { // body content }the body content only show if user admin. Oct 1, 2015 at 12:40 -
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If you looking it through grammatically so follow this.
function hook_block_view($delta = '') {
global $user;
$block = array();
switch ($delta) {
case 'demo_block1':
if (in_array('Admin', array_values($user->roles))) {
$block['content'] = t('Hello Admin');
}
break;
case 'demo_block2':
if ($user->uid) {
$block['content'] = t('Hello Authenticated User');
}
break;
}
return $block;
}
