How do I print the body of a node? [closed]

Question

I am struggling to work out how to print a node body on a page.

I normally use something like this print $node->field_manufacturer[0]['view']; but I am unsure how to print the body of a node.

How can I achieve it?

Answer 1

You can view the whole structure and content of a node by writing:

<pre><?php print_r($node); ?></pre>

And then choosing what deems appropriate.

To print the node body, you should use $node->content['body']['#value'].

Answer 2

For Drupal 7, a better style is to use field_get_items. E.g.:

<?php
  $body = field_get_items('node',$node, 'body');
  print $body[0]['value'];
?>

Answer 3

Just try this for Drupal 7

<?php print render($content['body'])?>

Answer 4

If $node is a node object obtained for example with node_load(), in Drupal 7 this is the structure of $node->body.

The language set for the node I used in the screenshot is English, and the input format is full HTML. As far as I can see, the content of the body is always contained in the "und" index, whatever language has been set for the node.

In Drupal 6, $node->body is a string.

If you implemented hook_nodeapi('view') (Drupal 6) or hook_node_view() (Drupal 7) the content of the body is found, respectively, with $node->content['body']['#value'], and $node->content['body'][0]['#markup'].

Answer 5

drupal 7 :

 <?php print $node->body['und'][0]['value'] ?>

Answer 6

The following usually works:

<?php print $node->body['value']; ?>

Answer 7

Perhaps a little late, but try the following, if you are using Drupal 6.

     <?php print $node->content['body']['#value'] ?>