Display Suite code field – how to use another image field conditionally

Question

In my content type I want to show the main image if the thumbnail field is empty. So I use the Display Suite code field and I enter the following code:

<?php 
dsm($entity);
if(empty($entity->field_thumbnail)){
    print_r('Thumbnail missing');
    // What code to put here to enable or render another image field 
}
?>

When the tumbnail is missing the above code works, but instead of text I want to display another image field, when the thumbnail is missing. I have tried everything I can think of, but the main image dose not show :-(.

Answer 1

It's because you have nothing in renderable format yet.

Look at function field_view_field

Returns a renderable array for the value of a single field in an entity.

Then change your code like this:

<?php 
dsm($entity);
if(empty($entity->field_thumbnail)){
    $renderable = field_view_field('node',$entity,'field_main_image',array('settings' => array('image_style' => 'thumbnail')));
    print drupal_render($renderable );
}
?>

Note that this is not the only way to get html from field values. You can use theme functions and load that with values you find on $entity object and print that if you wish.