Get Views field value in Twig template

Question

I'm trying to get the value of a field and use it as a class for a wrapper of another field within a Views display. So essentially what I need is to be able to get a string representation of the first field. The field already is a text field but when I try getting the content it doesn't just give me a string, which is what I need to be able to use is as a class for my second field.

I've tried using {{ fields.[field_name].content }} but that renders the twig template recommendation along with the data. I tried using the getValue() function, but that doesn't return anything. I tried passing the data through the raw twig filter but that doesn't return anything. I tried rendering the array using dpm and kint but they both give me way too much information and I can't narrow it down to what array item or object I need to use. I'm new to Drupal so maybe I'm not using Devel and Kint correctly to find what I'm looking for.

Is there a function I have to use to get the content data as a string or just raw, or is there some other way I can accomplish this?

I am using Drupal 8.1.

Answer 1

field.content is the rendered field. And in views that means it is no longer a render array, but the finally rendered markup. So this is very problematic to use it as a class name, not only because of twig debug.

Better use the row data, where you find the entity object with the field data from the database. Use clean_class to escape it for using it as a class name:

{{ row._entity.field_myfield.value|clean_class }}

Answer 2

I've tried using {{ fields.[field_name].content }} but that renders the twig template recommendation along with the data.

That is because you have twig debug turned on. If you turn off twig debug the recommendation will go away.

Answer 3

{{ fields.[field_name].content|striptags|trim }}
this helped me printing path and image url fields