On my controller for a custom page I've loaded an entity and I want to render, on the template for this custom page, only a field of the loaded entity. I would like to get the render array for this field.

Is it possible? I don't want to create a template for this content type only for this

3 Answers 3


This is an example for D8:

$node = Node::load('1');
$display_settings = array(
  'label' => 'inline',
$build = $node->body->view($display_settings);
  • How would I render $build?
    – liquidcms
    Jan 10, 2020 at 17:39

I would use the following code.

$field_to_render = field_view_field('model', $model, 'field_headerimage_image', 'full');
$field_to_render[$active_image]['#image_style'] = 'header_style';
$output = render($field_to_render[$active_image]);

I can't comment yet, otherwise I'd add this to the answer (https://drupal.stackexchange.com/a/206821/71534) but it's also helpful to know how to get the $display_settings for your field.

  1. Setup the field with Manage Display the way you want

  2. Then you can check the config (e.g. core.entity_view_display.node.page.teaser.yml

  3. Find the field you want under the content key in the root of the yml file, which may look like this:

        label: hidden
        type: text_default
        weight: 22
        settings: {  }
        third_party_settings: {  }
        region: content
  4. So in PHP you could set $display_settings to:

    $display_settings = array(
      'label' => 'hidden',
      'type' => 'text_default',
      'weight' => 22,
      'settings' => array(),
      'third_party_settings' => array(),
      'region' => 'content'

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