3

I have a body field view template:

<?php

/**
 * @file
 * This template is used to print a single field in a view.
 *
 * It is not actually used in default Views, as this is registered as a theme
 * function which has better performance. For single overrides, the template is
 * perfectly okay.
 *
 * Variables available:
 * - $view: The view object
 * - $field: The field handler object that can process the input
 * - $row: The raw SQL result that can be used
 * - $output: The processed output that will normally be used.
 *
 * When fetching output from the $row, this construct should be used:
 * $data = $row->{$field->field_alias}
 *
 * The above will guarantee that you'll always get the correct data,
 * regardless of any changes in the aliasing that might happen if
 * the view is modified.
 */
?>
<?php print $output; ?>

What I want is:

if nid == 1
print $output =  view_embed_view('my custom view')
else
print $output;

How can we do this?

Note: I'm already using the Views Field View module, but can't figure out as how to apply this condition of nid.

5
  • 1
    I don't understand your question....
    – Jimmy Ko
    Aug 3, 2016 at 10:23
  • Actually I want to embed view on basis of node id. So if node id == 1 or something else, I will replace body field content with some other view. Aug 3, 2016 at 10:34
  • Views Field View may help.
    – Jimmy Ko
    Aug 3, 2016 at 10:48
  • I'm already using this module, but can't figure out as how to apply this condition of nid? Aug 3, 2016 at 11:23
  • 1
    You can take a look my answer in other post.
    – Jimmy Ko
    Aug 3, 2016 at 11:36

1 Answer 1

4

In view template file of body field, write this code;

$nid = $row->nid;
$body = $row->body;
if($nid == 1):
  $view = views_get_view('VIEWS_MACHINE_NAME');
  $view->set_display('DISPLAY_ID');
  $new_view = $view->preview('DISPLAY_ID');
  print render($new_view);
else :
  print $body;
endif;

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