Get all nodes of given type

Question

I would like to get all nodes that are of my_custom_type type in Drupal 8.

I know I can get all the nodes (of any type) with \Drupal\node\Entity\Node::loadMultiple() and the list of all types by \Drupal\node\Entity\NodeType::loadMultiple().

But how to get only the nodes of given node type?

I really don't want to use specialized module for it (if it's possible), just keep it as simple as possible. I will use the solution in my custom module.

And loading all the nodes with \Drupal\node\Entity\Node::loadMultiple() and then check their type in foreach would hit the performance too much.

Answer 1

You can use Drupal::entityQuery() & Node::loadMultiple() to load all the nodes of your given type:

$nids = \Drupal::entityQuery('node')->condition('type','my_custom_type')->execute();
$nodes =  \Drupal\node\Entity\Node::loadMultiple($nids);

Answer 2

Another way to do this would be using this snippet of code:

$values = [
  'type' => 'page'
];
$nodes = \Drupal::entityTypeManager()
  ->getStorage('node')
  ->loadByProperties($values);

Answer 3

Usually you need published nodes, not all.

$nids = \Drupal::entityQuery('node')
  ->condition('status', 1)
  ->condition('type', 'YOUR-NODE-TYPE')
  ->execute();
$nodes = \Drupal\node\Entity\Node::loadMultiple($nids);

Answer 4

Its actually very easy,

Drupal::entityTypeManager->getStorage('node')
  ->loadByProperties(['type' => 'content_type', 'status' => 1])

If you would like all nodes also unpublished just use:

Drupal::entityTypeManager->getStorage('node')
  ->loadByProperties(['type' => 'content_type'])