3

I've created UnitTest based class for my service.

In one of my tested methods from service class I have code like:

if ($node->hasField('field_foo')) {
  $section = $node->field_foo->entity;
}

I've created mock for Node class and I know how to "emulate" hasField. However, how to mock this line:

$section = $node->field_foo->entity

I'd to set $section to be a Term object (or mock). Is this even possible? Now my test falls with an error:

Trying to get property of non-object

but this is clear why. I'm using just mock, not real Node object.

2
  • Your question is too vague. Can you please post your entire test method and the method you are trying to test? – nathandentzau Oct 2 '16 at 17:46
  • All that I can add is that $section is returned from this method, so that's why line that I wanted to distinct is important – Codium Oct 2 '16 at 21:44
0

Yes, magic methods afaik can't be mocked.

You can use get('field_foo')->entity which does exactly the same as __get(), at least in this case. And then make that return a stdClass object with a ->entity property. That's not exactly the same as what really happens, but it will work in the same way for your code.

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