I'm trying to return the 404 page instead of 403 response for unpublished nodes in Drupal 8.

I tested kernel response subscriber, but found the code I was using would only change the status code to 404 from 403, not actually display the 404 page. So maybe someone can show me how to generate a 404 page Response object there?

This is the code I was using:

class ResponseSubscriber implements EventSubscriberInterface {

   * {@inheritdoc}
  public static function getSubscribedEvents() {
    return [KernelEvents::RESPONSE => [['alterResponse']]];

   * Change status code to 404 from 403 if page is an unpublished node.
   * @param FilterResponseEvent $event
   *   The route building event.
  public function alterResponse(FilterResponseEvent $event) {
    if ($event->getResponse()->getStatusCode() == 403) {
      /** @var \Symfony\Component\HttpFoundation\Request $request */
      $request = $event->getRequest();
      $node = $request->attributes->get('node');
      if ($node instanceof Node && !$node->isPublished()) {
        $response = $event->getResponse();
        // This changes the code, but doesn't return a 404 page.



I finally resorted to removing this response subscriber completely and used hook_node_access like this:

use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Drupal\Core\Access\AccessResult;

function unpublished_404_node_access(\Drupal\node\NodeInterface $node, $op, \Drupal\Core\Session\AccountInterface $account) {

  if ($op == 'view' && !$node->isPublished()) {
    if (\Drupal::moduleHandler()->moduleExists('workbench_moderation') && $account->hasPermission('view any unpublished content')) {
      return AccessResult::neutral();
    elseif (\Drupal::routeMatch()->getRouteName() == 'entity.node.canonical' && \Drupal::routeMatch()->getRawParameter('node') == $node->id()) {
      throw new NotFoundHttpException();
      return AccessResult::neutral();

  return AccessResult::neutral();

This seems to be in line with several answers on this site for Drupal 7. But I wanted to see if anyone has a better way of doing this either with a KernelEvent subscriber, rather than hook_node_access. It seems like what I want to do is test if a node is returning a 403 and then generate a new response with the 404 page and 404 status code. I'm not sure how to do that.

1 Answer 1


You can try to do this earlier in an exception instead of a response subscriber. Extend HttpExceptionSubscriberBase, so you need less code to do this. Then replace the 403 with a 404 exception with the method $event->setException()



namespace Drupal\mymodule\EventSubscriber;

use Drupal\Core\EventSubscriber\HttpExceptionSubscriberBase;
use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;

class Unpublished404Subscriber extends HttpExceptionSubscriberBase {

  protected static function getPriority() {
    // set priority higher than 50 if you want to log "page not found"
    return 0;

  protected function getHandledFormats() {
    return ['html'];

  public function on403(GetResponseForExceptionEvent $event) {
    $request = $event->getRequest();
    if ($request->attributes->get('_route') == 'entity.node.canonical') {
      $event->setException(new NotFoundHttpException());



    class: Drupal\mymodule\EventSubscriber\Unpublished404Subscriber
    arguments: []
      - { name: event_subscriber }

This replaces all 403 exceptions for canonical node routes. You can get the node object $request->attributes->get('node') if you want to check if this is really because the node is unpublished.

  • Thank you, I have tested it out and it works great! This is just the kind of thing I was looking for.
    – oknate
    Commented Mar 14, 2017 at 14:59

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