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I have a custom form that submits via AJAX. On form error, i simply return the whole form on my callback function, and the HTML is replaced, but i want it to open a modal dialog on success. What is the best way to do this? This is what i'm currently doing (i don't like this solution because i can't clear the form values, among other things):

    public function ajaxCallback(array &$form, FormStateInterface $form_state) {

        drupal_get_messages(); // Hide the status messages

        $form_state->setRebuild(TRUE);

        if ($errors = $form_state->getErrors()) {

          return $form;
        }
        else {

          $response = new AjaxResponse();

          $title = 'Consectetur adipiscing elit';
          $text  = 'Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.';

          $response->addCommand(new OpenModalDialogCommand($title, $text));

          return $response;
        }
      }
11
  • I did something very similar in a similar scenario.
    – Eyal
    Commented Jul 12, 2017 at 10:53
  • Note that if you want to add the error messages to the AJAX form, you can just add the messages element to the start of the form.
    – Eyal
    Commented Jul 12, 2017 at 10:54
  • What would really be perfect form me would be able to always return ajax commands. The problem is if i simply return $response->addCommand(new Command('#my-form-wrapper', drupal_render($form))); the form gets broken. the only way for ajax to keep functioning is returning the whole form, or not touching it at all. Commented Jul 12, 2017 at 11:03
  • When you return the form array, drupal converts it to AJAX commands, so technically you can write those commands yourself, though i don't recommend it.
    – Eyal
    Commented Jul 12, 2017 at 11:05
  • 2
    @JoséTrindade, this is exactly the opposite, you should not render early, because ajax commands which add html have a method to render and at the same time preserve the attachments most ajax forms need.
    – 4uk4
    Commented Jul 12, 2017 at 20:37

1 Answer 1

0

Here is what i came up with (many thanks to @4k4):

    public function ajaxCallback(array &$form, FormStateInterface $form_state) {

        drupal_get_messages(); // Hide messages

        $form_state->setRebuild(TRUE);

        if ($errors = $form_state->getErrors()) {

           return $form; // Simply Return the form
        }
        else {

         $response = new AjaxResponse();

         $title = 'Consectetur adipiscing elit';
         $text  = 'Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.';

        $response->addCommand(new OpenModalDialogCommand($title, $text));

        // Or add the $form as parameter to an HTML command.
        $response->addCommand(new ReplaceCommand('#my-form-wrapper', $form)); 

        // Do notice i added a wrapper to my form in the buildForm() method:
        // $form['#prefix'] = '<div id="my-form-wrapper">';
        // $form['#suffix'] = '</div>';

         return $response;
    }

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