I have made a page that displays information about a user, much like a profile page.

Now I want users to be able to edit their information, so I added a button using twig tweak in user.html.twig:

{% if logged_in %}
<div class = "row"> 
    <a href ="{{ drupal_token('current-user:edit-url') }}" class = "edit-profile-btn col-lg-12">
      <div>Edit profile</div>
{% endif %}

enter image description here

This works fine, however the button is displayed on every profile page. I want to hide the button if a user is viewing another user's page.

Can this be done using an {{ if statement }} to check if the viewed page belongs to the logged in user?

1 Answer 1


To do this right you will need to use this combination of tests.

Is the user logged in {% if logged_in %} ?

Does the user have the permission needed to edit their profile with {% if user.hasPermission('depends on your site setup') %}?

Is the owner of the node the same as the current user? {% if node.ownerId == user.id %}

NOTE: The snippets above are not tested. You may have to tweak to get the correct info (e.g. getOwnerId SHOULD equal node.ownerId.. but twig may have a different opinion).

  • I tried any statement containing an = but it gives me errors. Could you maybe give some more explanation on how to use your answer? I tried something like {% if user.current-user %} but this didn't work also
    – Rubenxfd
    Oct 18, 2017 at 7:46
  • Sorry, that was a typo on my part. Corrected the = to == in the answer, which is the correct syntax.
    – CG Monroe
    Oct 18, 2017 at 13:38
  • Thanks, that did at least not give me an error. Can you help me tweak it further? As I am using the user node with a specific view (full), do I have to do anything different? I tried using {% if user--full.ownerId == current-user.uid %} but it still displays on every page.
    – Rubenxfd
    Oct 18, 2017 at 14:46

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