How can I determine from within a module or theme if the current page is an Apache solr search results page?

  • 2
    Which way are you trying to identify it? From within code?
    – John Fiala
    Mar 2, 2011 at 21:01
  • Are you referring to a Google search result (from an external site)? Or are you referring to a Drupal search result (from an internal search)? And what is the context (block, module, template, etc) ? Mar 2, 2011 at 21:09

5 Answers 5


If you're trying to determine from a module then you can check if the page is the search results page via the path arguments using the arg() function.

if (arg(0) == 'search') {
else {
  • This is what I have used before. It worked pretty well. Mar 3, 2011 at 0:08
  • 1
    You might have to test for an arg(1) as well to ensure it is actually a 'results' page and not the search landing page
    – wiifm
    Mar 3, 2011 at 7:02
  • this only works if you are using the standard paths. Mar 3, 2011 at 8:02
  • What Jeremy said, for starters... but you should be able to check for whatever paths you're using :-) Now, you might also want to check to see if there's a third arg (arg(2)) present, which means you're on a search result page... Mar 3, 2011 at 18:12

From a theming point of view you could simply use

<?php if ($search_results) : ?>
    <!-- Do this on search results pages -->
<?php endif; ?>

$search_results should only return true if you are on a search results page.

If you're looking into styling the results themselves you might want to look into search-result.tpl.php


If you are looking to find if solr has been searched you can use the apachesolr_has_searched() function.

This won't indicate if you are on a search results page, as once you start using solr views the definition of a search results page is fuzzy, but it can tell you if a solr search has been performed.

Just for reference apachesolr_static_response_cache() will give you solrs' response, and apachesolr_current_query() will give you information on the query.


To verify if a page is a search page, you should verify the first path element of the current URL is search, and the second path element is the name of a module that implements hook_search(). (I used a temporary variable, and added extra parentheses just to be make the code more readable.)

$bool = ((arg(0) == 'search') &&
  ($module == arg(1)) && module_invoke($module, 'search', 'name')
if ($bool) {
  // The page is a search page returned from apachesolr.module.

In the specific case, considering that you want to verify if a page is a result page returned from apachesolr.module, the code can be simplified as follows:

if ((arg(0) == 'search') && (arg(1) == 'apachesolr')) {
  // The page is a search page returned from apachesolr.module.

The reason the generic code can be simplified is that you know the name of the module, and that module surely implements hook_search().
The generic code verify the value returned by hook_search() when the last parameter is equal to "name" because there are modules that implement hook_search() only partially. At least that what I discovered when I was debugging the code of OpenSearch Feed.


In case you are talking about a theme or module you could check the current URL/path if it begins with "search".

  • Funny how my answer is downvoted without an explaining comment, while other answers with the same solution are upvoted... Mar 3, 2011 at 10:13
  • 4
    I didn't downvote, but it's probably because of the lack of a code sample or something more substantive :-/ Mar 3, 2011 at 18:13

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