Filter to only nodes with an image in an imagefield

Question

I'm sure this can't be difficult, but it has me stumped.

In my view, I want to exclude nodes that do not have an image in a specific field. The field allows an unlimited number of images. I don't care about the exact quantity, just that there are more than 0.

How do I create this filter and what do I filter on?

Answer 1

In the edit screen of your view, click "+" symbol in the filters box to add a new filter. Settings for filter:

• Select your imagefield you want to filter on (ex "Content: My Image (field_my_image) - list") and click the "Add" button
• Check True and click "Update"

Now only your selected nodes that has an image in the imagefield will show in the view

Answer 2

If you filter by one of the image field's subfields (e.g. fid, delta, language, width, height, etc), you may end up with duplicate rows in the results, which is usually not desirable. To avoid that, just filter by the "image_field_name:delta" field instead, setting the Operator to "Is equal to" 0. That should filter out all rows without images, and without creating duplicates.

Answer 3

Often, you will not have a True/False option. In this case, click to add Filter, select an image which ends with :fid. FID is short for File ID. Select "Is not empty (NOT NULL)" from the select menu.

This would require the File ID to be present; and File IDs cannot be present without the file.

Answer 4

I tried the Laxman13 instruction, but that process didn't worked to me. I think that the listing value is related to a node display context.

In my case, I had to create a relationship with my CCK image field (Content: Image - fid) and then make a file ID filter (File: File ID) using the previous relation with a "not empty" validation.