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In my task I need to get the distinct number of the nodes of some content type. How can I do it?

$query = $this->connection->select('node', 'node')->condition('node.type', $type);
$query->addExpression('COUNT(*)');
$query->innerJoin('taxonomy_index', $id,  "$id.nid = node.nid  AND $id.status = 1");
$count = intval($query->execute()->fetchField());

As the node may have multiple values for the field, in the end it counts all nodes and produces the wrong output. Therefore I need to get distinct number of nodes.

Just adding $query->distinct(); doesn't bring anything. Could you please help me how can I solve the issue?

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You can use Drupal EntityQuery class like this:

$count = \Drupal::entityQuery('node')
    ->condition('status', 1)
    ->condition('type', $type)
    ->count()->execute();
  • maybe I should have mentioned in the description that i perform an innerjoin as well with "taxonomy_index" table, and it results in wrong counting. That's why I am searching a way to reduce duplicates – badm Sep 18 '18 at 8:17
  • Then please update the question and include the missing code so that others can help as well – Ismail Cherri Sep 18 '18 at 8:18
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If you want to retrieve distinct number of the nodes of content type $type.
Try this.


use Drupal\Core\Database\Database;

//- Retrieves a \Drupal\Core\Database\Connection which is a PDO instance
  $connection = Database::getConnection();
    $query = $connection->select('node', 'node')
        ->fields('node', array('nid'))
        ->condition('node.type', $type, '=')
        //- Force filtering of duplicate records in the result set.
         ->distinct()
        ->countQuery()
        ->execute();

    $count = $query->fetch(\PDO::FETCH_NUM);

Ps: you still have to add Your desired innerJoin to the query take a look to Select::innerJoin .

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