I can call a view with contextual filters without any problem, but when I add exposed filter value $view->setExposedInput to the call, I just does not work, the exposed value is not applied and being ignored. The filter 'price' field is set in the views filters options and i tried both exposing it and not exposing it to visitors without any luck. I call this view from my controller class and I need to pass the arguments to both filters and I do not need exposed form to be displayed to the user.

$view = Views::getView($view_id);
if (is_object($view)) {
  $filters = [
       'price' => 500, //my exposed filter value       
  $view->buildRenderable($display_id, $args);
  $content = $view->render();
  • I do not need exposed form to be displayed to the user ... you just contradicted your question's title
    – No Sssweat
    Commented Dec 27, 2018 at 2:37
  • Well, this is not so important for now.. the thing I want to do is to render a view results programmatically with passing contextual and exposed filters data.
    – JetSet
    Commented Dec 27, 2018 at 17:12
  • setting Use Ajax: True may be relevant here Commented Oct 13, 2020 at 6:33

1 Answer 1


You can use this code in custom block can also set permission.

 use Drupal\Core\Form\FormState; 
 use Drupal\views\Views; 
   $form = []; 
   $view_id = 'blog_landing_page'; 
   $display_id = 'page_1'; 
   $view = Views::getView($view_id);     
   if ($view) { 
 $form_state = (new FormState()) 
   'view' => $view, 
   'display' => &$view->display_handler->display, 
   'rerender' => TRUE, 
   $form_state->set('rerender', NULL); 
 $form = \Drupal::formBuilder()->buildForm('\Drupal\views\Form\ViewsExposedForm', $form_state); 

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