I am wondering if it is possible to stack two
ajax_command_replace commands. In other words, to have code that looks like this:
<br> $commands = array();<br> $commands = ajax_command_replace($selector1, $data1);<br> $commands = ajax_command_replace($selector2, $data2);<br> ajax_deliver(array('#type' => 'ajax', '#commands' => $commands);<br>
and then to expect both commands to run?
When I try this, the first command runs just fine, but the second command does not. I have reversed the order of the two commands, and sure enough, the (new) first command now runs, but the (new) second command does not. I have also looked at the page after the
ajax_deliver has run, and the first command did not destroy the html on the page, so the second command's selector is still there. I have also added a dummy
ajax_command_alert just to be sure that I can run multiple commands, and that works as well.
An added comment: If you use ajax_command_replace, you lose the tags on the selector you have chosen. Two options to get around this are (1) Use ajax_command_html (which retains the outer tag) or (2) include the outer tag information in the html for the ajax_command_replace.I still, however, cannot stack two ajax_command_replace or ajax_command_html commands.