In a drupal 7 website, I have a view that is based on a custom table. I have a status column in that custom table, which is type of integer and has 0 or 1 value, and in a view I want to add exposed filter with dropdown, with values somehow like below

$options[0] = 'No';
$options[1] = 'Yes';

So that a user can choose a value from dropdown and filter out data.

So in my views.inc file I have implemented hook_views_data(), then I have added the following code to make that field accessible in a view

$data['custom_users']['status'] = array(
      'title' => t('User Status'),
      'help' => t('User Status'),
      'field' => array(
        'click sortable' => TRUE,
      'filter' => array(
        'handler' => 'views_handler_filter_numeric',
      'sort' => array(
        'handler' => 'views_handler_sort',

Now when I am trying to add exposed filter using this field I am not able to make it available as dropdown. I am only getting a textfield as exposed filter for this field.

Any help will be appreciated.

  • Have you checked this article? atendesigngroup.com/articles/… Nov 3, 2020 at 8:21
  • @PatrickScheffer Hello. Thanks for your response. Yes I have checked that article, and method mentioned in it somehow works with actual field table, in my case I have only one custom table that stores form submissions, some simple values like name and other details. So there I have a status column that holds either 0 or 1 value. In views I was expecting to have drop down option, like in case of node you can have filter with Published & Unpublished options in dropdown.
    – Vik Durve
    Nov 3, 2020 at 11:52
  • How does your views_handler_filter_numeric class look? Nov 3, 2020 at 12:05

1 Answer 1


You can use hook_form_alter() for this. simply change the field type to select and add your options. here is my working code

// implements hook_form_alter
function project_form_alter(&$form, &$form_state, $form_id) {
  if ($form_id === 'views_exposed_form') {
    $view = $form_state['view'];
    // add your view name in 'view_name'.
    if ($view->name === 'view_name') { 
      // Checking status field is exists or not.
      if (isset($form['status'])) {
        $form['status']['#type'] = 'select';
        $form['status']['#empty_value'] = '';
        $form['status']['#empty_option'] = 'All';
        $form['status']['#options'] = array('0' => 'No', '1' => 'Yes');
        $form['status']['#size'] = 1;
        $form['status']['#attributes'] = array('id' => 'status-list');

hope this will work :).

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