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I have two content types, one (A) refering to the other (B). I also have two languages and I want to create a view where I show a list of all content type nodes of type A with an exposed filter, filtering the refering content type nodes of type B. this will show me all nodes of A that refer to B. so my filters are

  • content type (A)
  • language (en)
  • refering node (exposed)

this works great but inside my exposed filter list of all nodes of type B every node is shown two times, representing every language translation. I now want to only show the english nodes of type B in the exposed filter list. how could I do that? thnx!

ps: I tried to use the filter groups, but this did not work.

  • How are you planning to select the language for the exposed filter? – amateur barista Aug 1 '12 at 17:13
  • I only wanted to show the english (original) ones. – headkit Aug 2 '12 at 13:18
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The Views exposed filters block is a Drupal form, one that can be modified via a hook_form_alter or hook_form_FORM_ID_alter implementation. Here is a simple sample implementation of the more generic hook_form_alter.

/**
 * Implements hook_form_alter.
 */
function foo_helper_form_alter(&$form, &$form_state, $form_id = NULL) {
  if($form['#id'] == 'views-exposed-form-content-page') {
    // Do something with mah filters...
  }
}

If you are in doubt of what #id to use, you can always just implement this hook, go to your Views page, and watch the output of the $form variable to figure out what is the correct id to use. If you are in D7, the ID you are looking for will most likely be prepended with views-exposed....

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