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I'm writing a module with a custom form. I would to add in this a form a field from an existent content type, with values.

For example: I've a content type "article" wth a node reference field "field_ref".

In my custom form I want to get this "field_ref" field, with values. Is it possible?

I think that I could get the entire form and then get only the field but I don't like this solution :)

2 Answers 2

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You can build a custom autocomplete text field to filter node reference results. Check this link http://timonweb.com/how-create-ajax-autocomplete-textfield-drupal-7 to build autocomplete text field.

You just need to change the query in above implementation.

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Assuming your field is a list type, you can grab the allowed values from the field using the field_info_field() function:

$info = field_info_field('field_states');
$options = $info['settings']['allowed_values'];

$form['work_state'] = array(
  '#title' => t('Work State'),
  '#type' => 'select',
  '#options' => $options
);

I got hint from this link of Stack Overflow

Check this link again from stackoverflow. https://stackoverflow.com/questions/11225158/drupal-7-programmatic-field-definition

This allows you to create node reference field

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  • This is ok, but I need to create a node_reference field, populated from values of a node (that I get with a view). I'm now searching api to create node_reference field
    – arrubiu
    Commented Sep 21, 2012 at 10:40
  • check my edit of answer Commented Sep 21, 2012 at 10:47
  • getting a list is ok, also add values from a view or a query. But I need to create in the form a node_reference field
    – arrubiu
    Commented Sep 24, 2012 at 14:05

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