views related content block // show content with specific initial letter

Question

i have a content-type with this fields:

title field
starting letter // term reference -> stores term in vocab "starting letter"
car brand // term reference -> stores term in vocab "car brand"
car model // term reference -> stores term in vocab "car model"
Image field

i have created a view that hast the url: example.com/vehicles/audi (the term audi comes from the vocab "car brand" in views this looks like vehicles/%)

on this page with the url example.com/vehicles/audi i want to show a block that contains a list of other cars which name starts with the letter A like:

Acura
Alfa Romeo
AMC
Ascari

the same should be work with brand starting with B, C and so on. i need a contextual solution.

my problem and what i dont unterstand: how do i set this thing up, because i dont have the term "A" in my url which i could filter with the contextual filter. i just have the term "audi". can anyone help me please?

Answer 1

Set argument for second view using hook_views_pre_view().

$view->set_arguments(array('A'));

Answer 2

I never use php in admin interface, in my opinion it's not right. Because later it's too difficult to remember where you place your custom logic... I advise you to create a custom module and place your code there.

As for your method, I guess PHP contextual filter requires returnable value. So let's try this:

$parent_view = views_get_page_view(); // Get vehicle view
$arg = $parent_view->args[0]; // Get vehicle view argument
$letter = $arg[0]; // First letter of argument
return drupal_strtoupper($letter);