I have created a HTML anchor link. Now i need to convert this link to Drupal's link using l() function. But i am not getting what i want. I am new to this Drupal environment.

HTML Link :

<a href="#" onclick="loadQtiPlayer('.$targetPath.','.$targetWindowHeight.','.$targetWindowWidth.')" id="qtiStatQuiz1">'.START_QTIQUIZ.'</a>

What i have tried is,

l('Start QTI Quiz', '#', array('','onclick' => "loadQtiPlayer('.$targetPath.','.$targetWindowHeight.','.$targetWindowWidth.')"));

This is not working. I am using Drupal 6.14.

Can anyone point out where is the issue?

$current_path = check_url(drupal_get_path_alias($_GET['q']));
$onclick = 'loadQtiPlayer(' . $targetPath . ',' . $targetWindowHeight . ',' . $targetWindowWidth . ')';
print l('Start QTI Quiz', $current_path, array('fragment' => ' ', 'attributes' => array('onclick' => $onclick)));
  • EDIT: added filter_xss instead of check_url... Not sure which is more safe/efficient in this case. :/
    – jerdiggity
    Apr 22 '13 at 8:37
  • Wow.. Works like a charm. Thank you man for this awesome answer.
    – Edwin Alex
    Apr 22 '13 at 8:42
  • 1
    Use check_url(), filter_xss() is for escaping HTML from content that will be displayed on the screen.
    – rooby
    Apr 25 '13 at 5:16
  • @rooby Thanks... I figured as much, if for no other reason than less resource-intensive. In fact that's how I originally had it posted, but-- well the "but" is not important... Changing back. :)
    – jerdiggity
    Apr 25 '13 at 7:39

You need to use the fragment option to add a fragment to the URL. l() makes it pretty difficult to get an empty fragment, but you can get very close to it with a little hack:

$link = l('Start QTI Quiz', '', array('fragment' => ' ', 'external' => TRUE)));

That'll do the trick for Drupal 6 & 7.


In this case as the href is pointing at any content there's no point in using the l() function at all. You may as well code the A tag directly as it's not really a link.

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