Display a custom field of a content type in template with PHP?

Question

I'm using Drupal 7. I have a content type called Widget. One of the custom fields is field_widget_position. When I did a <?php print_r($page); ?> in the template, I can see the key-value pair of field_widget_position buried deep in the array. Is there an easier way to get a handle on field_widget_position instead of typing <?php echo $page['somefield']['somefield2']['somefield3']['etc....']['field_widget_position']; ?>?

Answer 1

$node->field_widget_position['en'][0]['value']

This is a bad solution.

The right solution is

render(field_view_field('node', $node, 'field_widget_position'));

or

render(field_view_field('node', $node, 'field_widget_position', array('label' => 'hidden')));

if you don't want to print a label.

See http://www.computerminds.co.uk/articles/rendering-drupal-7-fields-right-way for more info.

Answer 2

I found the answer.

$node->field_widget_position['en'][0]['value']