I have a node and want to get all the taxonomy terms assigned to the node.
In drupal 6 I could use $node->taxonomy
and the taxonomy_*
functions but these don't exist in drupal 7.
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Sign up to join this communityTaxonomy terms are implemented in fields in Drupal 7. Assuming you have defined a taxonomy field named field_category for your content type, you can access it as:
$language = 'und'; // or will be provided by some Drupal hooks
foreach ($node->field_category[$language] as $delta => $value) {
$term = taxonomy_term_load($value['tid']);
}
If you don't have access to the field name, probably the easiest way for nodes is to query the database directly:
$results = db_query('SELECT tid FROM {taxonomy_index} WHERE nid = :nid', array(':nid' => $node->nid));
foreach ($results as $result) {
$term = taxonomy_term_load($result->tid);
}
Keep in mind though, that you may end up dealing a jumble of terms from different vocabularies if you have more than one taxonomy field.
taxonomy_term_load_multiple($results->fetchCol());
to load the terms in a single query.
field_get_items('node', $node, 'field_category')
to get the fields in the correct language.
Here's a very generic way to grab all terms without specifying field names and no db_query:
function example_get_terms($node) {
$terms = array();
foreach (field_info_instances('node', $node->type) as $fieldname => $info) {
foreach (field_get_items('node', $node, $fieldname) as $item) {
if (is_array($item) && !empty($item['tid']) && $term = taxonomy_term_load($item['tid'])) {
$terms[] = $term->name;
}
}
}
return $terms;
}
if (arg(0) == 'node' && is_numeric(arg(1))) {$nid = arg(1);}
to get the nid
and $node = node_load($nid);
in order to make your function work.
Apr 7, 2017 at 8:40