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i want make a photo gallery with drupal and i need to:

  1. a download button for current node picture

  2. an embed code that allow visitor to use photo on other Websites. like this: enter image description here

i have some experience with Drupal and reading PHP codes, but no experience with writing PHP codes. i tried to make a block in bottom of node picture with PHP filter and following content:

<pre><a href="<?php t('[node:url]'); ?>" title="<?php t('[node:title]'); ?>"><img src="<?php t('[node:field_image]'); ?>"></a></pre>

this code not work. please help me.

many thanks :)

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1 Answer 1

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To translate the tokens in their values, you can use:

token_replace

e.g:

$nid = token_replace('[node:nid]', array('node' => $node));

You need to be able to pass the required parameters for that token, e.g $node for node tokens.

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  • using: <?php $nid = token_replace('[node:nid]', array('node' => $node)); echo $nid; ?> gives error: Notice: Undefined variable: node in eval() (line 2 of /srv/http/g/modules/php/php.module(80) : eval()'d code).
    – Ma3x
    Nov 24, 2013 at 10:49
  • As mentioned, you'll need to get the $node object first. That depends on the code context. Sometimes, if on a node page, it's $node = menu_get_object('node');
    – David Thomas
    Nov 24, 2013 at 21:04
  • as i said i have not experience to write PHP codes, and thanks to show me the way directly. i used this and worked: <a href="<?php $node = menu_get_object('node'); $url = token_replace('[node:url]', array('node' => $node)); echo $url; ?>" title="<?php $node = menu_get_object('node'); $title = token_replace('[node:title]', array('node' => $node)); echo $title; ?>"><img src="<?php $node = menu_get_object('node'); $field_image = token_replace('[node:field_image]', array('node' => $node)); echo $field_image; ?>"></a> thanks man :)
    – Ma3x
    Nov 24, 2013 at 21:33

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