New answers tagged ajax
1
Just added a video link to show you : imgur.com/EmVha6e
You just need to add a conditional to check if it's not ajax
$request = \Drupal::request();
$is_ajax = $request->isXmlHttpRequest();
if (!is_ajax) {
// code that sets the filter initial value
}
Credit: How can I detect AJAX request inside Drupal?
0
This code uploads one file with Ajax, attaching it to an existing node's file field. The content type is file_test, and the field is field_da_files.
(I'm not a professional programmer, so there are no doubt better ways to do this.)
Here's some HTML/JS that talks to a Drupal controller. It sends the node id, and the file to be stored.
In uptest.html.twig:
...
0
SOLUTION: Got this working with the following. You have to set the #ajax property on the widget
// Set the ajax function to run on the change of filing category.
$form['category']['widget']['#ajax'] = [
'callback' => '_ajax_form_category_change',
'event' => 'change',
'wrapper' => 'ajax_id_data_type',
'method' => 'replace',
];
2
Your AJAX needs to have a target ID where it will put your AJAX output. You declare that ID in the wrapper key.
In your form_alter
'#ajax' => [
'callback' => 'xyz_user_signup',
'wrapper' => 'load-me-here-id', // This element is updated with this AJAX callback.
],
Then you need to wrap the field with this ID so AJAX replaces it.
$...
2
Ok, So thanks to 4k4 I now understand what i was doing wrong, and for the favour of everyone that will meet this issue again:
The form_alter is invoked as well when ajax callback is invoked.
by the time the execution got to my ajax callback (getAjaxArgumentsFields) the form_alter has already altered my form, so all i had to do was return the fields without ...
0
There is a little hack with php. And it works not only with Google, but with any website you don't control and can't add Access-Control-Allow-Origin *
We need to create PHP-file (ex. getContentFromUrl.php) on our webserver and make a little trick.
PHP
<?php
$ext_url = $_POST['ext_url'];
echo file_get_contents($ext_url);
?>
JS
$.ajax({
...
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