Hide html / code based on content type

Question

I'm using a block of code that shouldn't be displayed on certain content types (not blocks, but actual code). When I use this approach, I'm getting undefined variable and trying to get property of non-object errors:

<?php
    if(function_exists('views_get_page_view') && views_get_page_view() ||  arg(0) == 'user') {
      $showpage = "yes";
    }
?>

<?php if (((!empty($node)) || (!empty($showpage))) && (($node->type != 'article') && ($node->type != 'basic_page'))): ?>

(Show all this)

<?php endif; ?>

It's the check if the visitor is on a user related page that causes the errors, but I have no idea how to fix this. Can someone help me out?

Answer 1

$node isn't available on user pages. But when $showpage is set, you are checking a property on the $node object. This gets the two errors you are describing.

I'm not sure what you are trying to do but you can troubleshoot by breaking out your booleans. I find it helpful to break logic onto multiple lines whenever possible, so that other people (and I) can read it later.

From:

if (((!empty($node)) || (!empty($showpage))) && (($node->type != 'article') && ($node->type != 'basic_page'))):

To:

if (!empty($node) || !empty($showpage)) {
  if ($node->type != 'article' && $node->type !='basic_page') {
    // do that stuff
  }
} 

So - when $showpage is not empty but $node is, as on a user page, $node is undefined.

I'm not exactly sure what you are trying to do but I think it is along the lines of "show this stuff on node pages that are not basic page and not article, or when the $showpage variable is present.

In which case:

if ((!empty($node) && !in_array($node->type, array('article', 'basic_page'))) || !empty($showpage))

Or more readably,

if(function_exists('views_get_page_view') && views_get_page_view() ||  arg(0) == 'user') {
  $showpage = 'yes';
}
elseif (!empty($node) && !in_array($node->type, array('article', 'basic_page'))) {
  $showpage = 'yes';
}

if (!empty($showpage)) {
  // do that stuff
}

It isn't a one-liner, but the longer code is easier to read, troubleshoot, and prevent errors.

Answer 2

The easiest way to find the user is in user page or not is as follows

$ARG0 = arg(0);
$ARG1 = arg(1);
if($ARG0 == "user" && is_numeric($ARG1) ){
echo "user page";
}else{
echo "not user page";
}

Check this link if any queries

How to check if this page is user Profile Page

Answer 3

The intention of this all is to hide the main-container div on those content types. The setup I was trying was actually a bit looked too far. In fact, other pages that weren't nodes, but no views pages either (user, 404, sent-pages, module-related pages, ...) got trapped in the hidden container as well.

By breaking up the conditions (thanks for the tip @calebtr), I came up with this working solution:

<?php if ((!empty($node) && in_array($node->type, array('article', basic_page')))): ?>

  (Nothingness)

  <?php else: ?>

  (Show all content)

<?php endif; ?>

I'm having no "undefined" errors so far.