If Content Type Equals, then

Question

I'm trying to get run some code if the content type of the current page is equal to events. I am using Drupal 8.

However, I'm unable to write the if statement.

I've tried:

if ($node->type == 'events'){...}
if (Node::getType == 'events'){...}

I also saw this question, but I have no idea how to apply it.

Full code:

// Add og:event:start_date meta tag

function MY_THEME_preprocess_html(&$variables) {
  if ($node->getType() == 'events'){
    $time = [
      '#tag' => 'meta',
      '#attributes' => [
        'http-equiv' => 'og:event:start_date',
        'content' =>  $node->field_next_time->value,
      ],
    ];

    $variables['page']['#attached']['html_head'][] = [$time, 'og:event:start_date'];  
  }

}

Answer 1

You need to pull the node object out of the variables array.

$node = $variables['node'];

In certain preprocess functions this may not be available, so you can try the request service:

$node = \Drupal::request()->get('node');

The object must be of type Node. Therefore:

$node->getType() == 'events'

As Berdir mentioned, you should check and ensure that $node is a valid Node object to see if it is an instance of NodeInterface before operating on it. This will prevent fatal errors in the event that $variables['node'] is actually a node and not some ad-hoc variable created in code from which you can't call methods on:

Example 1 (using $variables array):

if (isset($variables['node']) && $variables['node'] instanceof NodeInterface) {
  $node = $variables['node'];
  $title = $node->getTitle();
  $type = $node->getType();
  // more code...
}

Example 2 (using the request):

$node = \Drupal::request()->get('node');

if (isset($node) && $node instanceof NodeInterface) {
  $title = $node->getTitle();
  $type = $node->getType();
  // more code...
}