Get User ID (not current) in a overridden views.tpl.php

Question

I'm using Drupal 7. I'm creating a view based on profile. It will show a list of all the people. Now I'm overriding the file views-view-unformatted--MYVIEW-page.tpl.php and I would like to add in the class of the row the ID of that user. If I write

global $users;
$user->uid;

of course it's giving me the id of the current user and not the uid of that profile.

I would like to create something like this: FIRST EXAMPLE:

    <?php
    $this_uid = I NEED THIS TOKEN;
    ?>
<ul>
    <?php foreach ($rows as $id => $row): ?>
      <li class="<?php print $classes_array[$id]; print " ".$this_uid;?>">
        <?php print $row; ?>
      </li>
    <?php endforeach; ?>
</ul>

I could create a custom text field in the view a put all the field inside the <li> tag like: SECOND EXAMPLE:

<li class="[user]">[name] [gender]</li>

and the file tpl.php will become

    <ul>
<?php foreach ($rows as $id => $row): ?>
            <?php print $row; ?>
        <?php endforeach; ?>
</ul>

But in this way I will lose the default row classes...

How can i get the first example? Do I need to create a view based on user instead of profile? Or should I use the second example?

Thanks in advance.

Answer 1

You should have a $views variable available with an array similar to $rows called $view->result[] that contains the unrendered/raw view results and just as long as you have a field in your output that has the uid in it, you will be able to access it directly here. (It can be a hidden field if you don't want it rendered later on) Put a drupal_set_message('<pre>' . print_r($view->result, true) . '</pre>'); or its equivalent in your template to take a look at it, but basically you should be able to use something like $view->result[$id]->FIELDNAME to access it or any other raw data.

Answer 2

Use views PHP field, set it as hidden, then use PHP to save needed value in this field. After that, views template will be able to get that value.

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