How to render field attribute in foreach

Question

I have a link field with multiple values. I want to display the link title for each of these fields. I can print the slide link titles individually but not using the foreach.

Currently I have:

<ul id="slideLinks">
<?php $slideshow_counter = 0; 
    $slide_link = $node->field_slideshow_link;
    print $slide_link['und'][0]['title'];
?>
<?php foreach ($slide_link as $link) : ?>
    <li><a class="slideControl" href="javascript:void(0);"><?php print $link['und'][$slideshow_counter]['title']; ?></a></li>
    <?php print $slideshow_counter; ?>
    <?php $slideshow_counter++; ?>
<?php
if ($slideshow_counter == 4)
    break;
endforeach;
?>

Answer 1

As I understand your question, I recommend you to use for statement, you can do this:

<ul id="slideLinks">
<?php $slide_link = $node->field_slideshow_link['und']; ?>
<?php for ($i = 0; $i < count($slide_link); ++$i): ?>
    <li><a class="slideControl" href="javascript:void(0);"><?php print render($slide_link[$i]['title']); ?></a></li>
<?php endfor; ?>
</ul>

This will print all your titles...

Answer 2

// Not enough points to comment on the good answer @mixerowsky

Drupal recommends using the field variable directly to avoid problems with language in the array (in your case ['und'] for undefined)

Field variables: for each field instance attached to the node a corresponding variable is defined; for example, $node->body becomes $body. When needing to access a field's raw values, developers/themers are strongly encouraged to use these variables. Otherwise they will have to explicitly specify the desired field language; for example, $node->body['en'], thus overriding any language negotiation rule that was previously applied.

So, extending the answer from @mixerowsky:

<ul id="slideLinks"> <?php foreach ($field_slideshow_link as $link) : ?> <li><a class="slideControl" href="javascript:void(0);"><?php print $link['title']; ?></a></li> <?php endforeach; ?> </ul>