2

I've searched/asked around without success.

I'm creating a custom Drupal 7 module, and I would like to render the code in an empty full template (not a page/node.tpl.php); by full template I mean a template containing the <html> tag.

Since now, I've used the following code but the template is rendered in page.tpl.php (render($page['content'])). 

function mymodule_theme() {
  return array(
    'adm_xyz' => array (
      'render element' => 'render',
      'template' => 'adm_xyz', //  template *.tpl.php
    ),
  );
}
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1 Answer 1

Reset to default
5

Your callback in hook_menu() will by default call drupal_deliver_html_page() which in turn calls drupal_render_page() where the page.tpl.php comes from.

It is possible to implement your own "delivery callback" method, which will be called by drupal_deliver_page() this is how the ajax is delivered in D7

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2
  • Good answer. Still I am curious what could possibly go wrong if you simply print + exit() in the page callback?
    – donquixote
    Commented Aug 18, 2017 at 19:41
  • Nothing else will be able to alter page structure. Late hooks will not get called.
    – Jeremy French
    Commented Aug 18, 2017 at 19:42

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