Getting $content of content type in template.php

Question

I am trying to get form that is used in content type template in template.php. I am creating node collections with EntityFieldQuery, and I am pulling field values of content type without problem.

But i need to access form, and add it to html stream that i create in template.php

In content type i can do

print render($content['add_to_cart']);

To get form out.

But now in template.php i need that form for specific nodes (im pulling them with EntityFieldQuery) as html, so i can include it to rest of the stream and send the data in variable, and simply output it where i need it (content type page.)

Thanks!

Answer 1

I'm not sure, if this is what you are looking. But if you want to embed a node-add form you could use the following code.

<?php
$node = new stdClass();
$node->type = 'machine_name_of_your_content_type';
module_load_include('inc', 'node', 'node.pages');
$output = drupal_get_form('machine_name_of_your_content_type_node_form', $node);
print $output;
?> 

Answer 2

Thanks to aerozeppelin, i implemented it this way:

in template.php ($node is fetched via EntityFieldQuery)

$add_to_cart = array( '#theme' => 'uc_product_add_to_cart',
'#form' => drupal_get_form('uc_product_add_to_cart_form_' . $node->nid, $node), );
$cart_form = drupal_render($add_to_cart);

where $cart_form contains html data form, that i included in my data stream!