Render only one field of an entity

Question

On my controller for a custom page I've loaded an entity and I want to render, on the template for this custom page, only a field of the loaded entity. I would like to get the render array for this field.

Is it possible? I don't want to create a template for this content type only for this

Answer 1

This is an example for D8:

$node = Node::load('1');
$display_settings = array(
  'label' => 'inline',
);
$build = $node->body->view($display_settings);

Answer 2

I would use the following code.

$field_to_render = field_view_field('model', $model, 'field_headerimage_image', 'full');
$field_to_render[$active_image]['#image_style'] = 'header_style';
$output = render($field_to_render[$active_image]);

Answer 3

I can't comment yet, otherwise I'd add this to the answer (https://drupal.stackexchange.com/a/206821/71534) but it's also helpful to know how to get the $display_settings for your field.

1. Setup the field with Manage Display the way you want

2. Then you can check the config (e.g. core.entity_view_display.node.page.teaser.yml

3. Find the field you want under the content key in the root of the yml file, which may look like this:

   content:
     body:
       label: hidden
       type: text_default
       weight: 22
       settings: {  }
       third_party_settings: {  }
       region: content
   

4. So in PHP you could set $display_settings to:

   $display_settings = array(
     'label' => 'hidden',
     'type' => 'text_default',
     'weight' => 22,
     'settings' => array(),
     'third_party_settings' => array(),
     'region' => 'content'
   );