Include Views output in href

Question

I am trying to create a custom button in Drupal 7. The link which the href should be equal to is dependent on the context such as the current UID.

I have created a view which normally has a plain text output as [title].

I want to use that text output as part of a link field such as

http://my-site.com/page/title

so I had written the code for the above link as such:

<a href="http://my-site.com/page/<?php $block = module_invoke('views', 'block_view', 'profile3-block_4'); print render($block[content]); ?>">LINK TEXT</a>

however the output seems as if it is placing part of a views div tag in the link instead. I tried stripping all html from the views block but no success. Anyone got ideas? Could it be an improper use of quotes?

Answer 1

print render($block[content]); returns a lot of tags. It simply cannot be a valid part of URL string. Also, be sure to avoid module_invoke in tpl files if feasible.

Answer 2

You can try like this:

$block = module_invoke('views', 'block_view', 'profile3-block_4'); 
$url = render($block[content]);
Assume your Output will be <div>TITLE</div>
then use **$url =  strip_tags($url);**
<a href="http://my-site.com/page/".$url>LINK TEXT</a>
It will be better to use **l()**
l(t('Link text'), 'http://my-site.com/page/'.$url);

If you are still facing issue request you to provide block html output.

Answer 3

If the url is one of the fields returned in the view query then you could access the raw data of the url by calling views_get_view_result($name, $display_id).

If it returns a uri then you may need to pass it though file_create_url() to get a url.

If the row returns a nid then the url might be generated via something like drupal_get_path_alias('node/' . $nid) (adapt as required for taxonomy terms, users, etc).